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07 December, 2010

Areas of parallelograms and triangles- Theorem

Theorem: Triangles having the same base and equal areas lie between the same parallels.

Given: ∆PQR and ∆SQR such that ar (∆PQR) = ar (∆SQR).

Construction: Draw PL and SM perpendicular to QR

To prove: PS//QR

(Length of perpendiculars between two parallel lines is equal)
Hence, PS// QR

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